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How to select 10 odd numbers from a list?
I'm using below python code to select the first 10 odd numbers from a list, But my results is weird, it seems like some numbers are not being excluded.
A=[2,4,3,1,2,3,2,3,1,2]
print(next(x for x in A if x%2!= 0))
Outputs as [1, 2, 2, 3, 3, 3, 4, 5, 5, 5]
Why there is no 4 in the output?
A:
You're modifying A, so you need to use a for loop instead of next (that's why you have a result of [1, 2, 2, 3, 3, 3, 4, 5, 5, 5])
for x in A:
if x%2!= 0:
print(x)
or
print(*(x for x in A if x%2!= 0), sep='
')
which is shorter and returns a list:
print(*A, sep='
')
The second method uses a generator expression (it's not a list, so we can't use the.pop() method), so it's better for memory usage. If you just want the numbers, use the first method
for x in A:
if x%2!= 0:
print(x)
Q:
Unable to read from the stream ac619d1d87
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